with these properties:\n\n#container > div {\n width: 466px;\n height: 288px;\n}\n\nThe greater than symbol is used here to single out the immediate child of the #container element, without affecting the grandchild or any of the more distant descendants.\n\nWe could go on to specify the precise pixel dimensions of every child element, but that means doing a lot of sums. It would be much easier if we just specified the dimensions for each element as a percentage of the width and height of its parent. This also has the advantage that if you change the size of the outermost container, all nested elements would be resized automatically \u2013 something that we shall exploit later.\n\n\n\n\n\n\n\nThe approximate value of 38.2% can be derived from (100\u2009\u00d7\u20091\u2009\u2212\u2009phi)\u2009\u00f7\u2009phi, where the Greek letter phi (\u03d5) stands for the golden ratio. The value of phi can be expressed as phi\u2009=\u2009(1\u2009+\u2009\u221a5\u2009)\u2009\u00f7\u20092, which is approximately 1.618. You don\u2019t have to understand the derivation to use it. Just remember that if you start with a golden rectangle, you can slice 38.2% from it to create a new golden rectangle.\n\nThis can be expressed in CSS quite simply:\n\n.cycle,\n.cycle > div > div {\n height: 38.2%;\n width: 100%;\n}\n.cycle > div,\n.cycle > div > div > div {\n width: 38.2%;\n height: 100%;\n}\n\nYou can see the result so far by visiting Demo One. With no borders or shading, there is nothing to see yet, so let\u2019s address that next.\n\nShading with transparency\n\nWe\u2019ll need to apply some shading to distinguish each segment of the spiral from its neighbours. We could start with a white background, then progress through shades of grey: #eee, #ddd, #ccc and so on, but this means hard-coding the background-color for every element. A more elegant solution would be to use the same colour for every element, but to make each one slightly transparent.\n\nThe nested
s that we are working with could be compared to layers in Photoshop. By applying a semi-transparent shade of grey, each successive layer can build on top of the darker layers beneath it. The effect accumulates, causing each successive layer to appear slightly darker than the last. In his 2009 article for 24 ways, Drew McLellan showed how to create a semi-transparent effect by working with RGBA colour. Here, we\u2019ll use the colour black with an alpha value of 0.07.\n\n#container div { background-color: rgba(0,0,0,0.07) }\n\nNote that I haven\u2019t used the immediate child selector here, which means that this rule will apply to all
elements inside the #container, no matter how deeply nested they are. You can view the result in Demo Two. As you can see, the golden rectangles alternate between landscape and portrait orientation.\n\n\n\nDemo Three).\n\n\n\nCSS3 specification indicates that a percentage can be used to set the border-radius property, but using percentages does not achieve consistent results in browsers today. Luckily, if you specify a border-radius in pixels using a value that is greater than the width and height of the element, then the resulting curve will use the shorter length side as its radius. This produces exactly the effect that we want, so we\u2019ll use an arbitrarily high value of 10,000 pixels for each border-radius:\n\n.cycle {\n border-radius: 0px;\n border-bottom-left-radius: 10000px;\n}\n.cycle > div {\n border-radius: 0px;\n border-bottom-right-radius: 10000px;\n}\n.cycle > div > div {\n border-radius: 0px;\n border-top-right-radius: 10000px;\n}\n.cycle > div > div > div {\n border-radius: 0px;\n border-top-left-radius: 10000px;\n}\n\nNote that the specification for the border-radius property is still in flux, so it is advisable to use vendor-specific prefixes. I have omitted them from the example above for the sake of clarity, but if you view source on Demo Four then you\u2019ll see that the actual styles are not quite as brief.\n\n\n\n\n\n\n\nFilling the available space\n\nWe have created an approximation of the Golden Spiral using only HTML and CSS. Neat! It\u2019s a shame that it occupies just a fraction of the available space. As a finishing touch, let\u2019s make the golden spiral expand or contract to use the full space available to it.\n\nIdeally, the outermost container should use the full available width or height that could accomodate a rectangle of golden proportions. This behaviour is available for background images using the \u201c background-size: contain; property, but I know of no way to make block level HTML elements behave in this fashion (if I\u2019m missing something, please enlighten me). Where CSS fails to deliver, JavaScript can usually provide a workaround. This snippet requires jQuery:\n\n$(document).ready(function() {\n\tvar phi = (1 + Math.sqrt(5))/2;\n\n\t$(window).resize(function() {\n\t\tvar goldenWidth = windowWidth = $(this).width(),\n\t\t\tgoldenHeight = windowHeight = $(this).height();\n\n\t\tif (windowWidth/windowHeight > phi) {\n\t\t\t// panoramic viewport \u2013 use full height\n\t\t\tgoldenWidth = windowHeight * phi;\n\t\t} else {\n\t\t\t// portrait viewport \u2013 use full width\n\t\t\tgoldenHeight = windowWidth / phi;\n\t\t};\n\n\t$(\"#container > div.cycle\")\n\t\t.width(goldenWidth)\n\t\t.height(goldenHeight);\n\n\t}).resize();\n\n});\n\nYou can view the result by visiting Demo Five.\n\n\n\n\n\n\n\nIs it just me, or can you see an elephant in there?\n\nYou can probably think of many ways to enhance this further, but for this study we\u2019ll leave it there. It has been a good excuse to play with proportions, positioning and the immediate child selector, as well as new CSS3 features such as border-radius and RGBA colours. If you are not already designing with golden proportions, then perhaps this will inspire you to begin.", "year": "2010", "author": "Drew Neil", "author_slug": "drewneil", "published": "2010-12-07T00:00:00+00:00", "url": "https://24ways.org/2010/golden-spirals/", "topic": "design"}